(2k+10)^2-4*(k+1)*5=0

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Solution for (2k+10)^2-4*(k+1)*5=0 equation: 



(2k+10)^2-4(k+1)*5=0

We multiply parentheses

(2k+10)^2-20k-20=0

We add all the numbers together, and all the variables

-20k+(2k+10)^2-20=0

We move all terms containing k to the left, all other terms to the right

-20k+(2k+10)^2=20

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